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0.7 abody describe 45m in 8thsec find out the acceleration of body. |
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Answer» Answer: a=6m/s^2 Explanation: Sn=45 n=8sec By USING 4th equation of MOTION Sn=u+a/2×(2n-1) By PUTTING values 45=0+a/2×(2×8-1) 45=a/2×(15) 90/15=a a=6m/s^2 |
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