1.

0.6 mole of NH_(3) in a reaction vessel of 2 dm^(3) capacity was bougth to equilibrium. The vassel was then found to contain 0.15 mole of H_(2) formed by the reaction 2NH_(3(g))hArrN_(2(g))+3H_(2(g)) Which of the following statement is true

Answer»

`0.15` mole of the original `NH_(3)` had dissociated at equlibrium
`0.55` mole of AMMONIA is LEFT in the vessel
At equilibrium the vessel contained `0.45` mole of `N_(2)`
The CONCENTRATION of `NH_(3)` at equlibrium is `0.25` mole PER `dm^(3)`

Answer :D


Discussion

No Comment Found