1.

0.5 mole of eachH_(2),SO_(2) and CH_(4) are kept in a container. A holewas made in the container. After 3 hours, the order of partial pressures in the container will be

Answer»

`P_(SO_(2))gtp_(CH_(4))gtP_(H_(2))`
`p_(H_(2))gtP_(SO_(2))gtP_(CH_(4))`
`P_(CH_(4))gtP_(SO_(2))gtp_(H_(4))`
`P_(CH_(2))gtP_(CH_(4))gtP_(SO_(2))`

Solution :Initially, partial pressure were equal. As `r PROP sqrt(1//d)` or `sqrt(1//m)` THEREFORE amounts diffused out in the same TIME will be `H_(2)gtCH_(4)gtSO_(2)`. Amounts left will be `H_(2)gtCH_(4)ltSO_(2)` or `SO_(2)gtCH_(4)gtH_(2)`
`:.p_(SO_(2))gtp_(CH_(4))gtp_(H_(2))`


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