1.

0.5 mol each of H_(2), SO_(2) and CH_(4) are ketp in a container. A hole was made in the container. After 3 hours, the order of partial pressure in the container will be :

Answer»

`pSO_(2) gt pCH_(4) gt pH_(2)`
`pH_(2) gt pSO_(2) gt pCH_(4)`
`pH_(2) gt pCH_(4) gtpSO_(2)`
`pSO_(2) gt pH_(2) gt pCH_(4)`

Solution :According to Graham.s law, the rate of effusion of a GAS is inversely proportional to square ROOT of its molar mass. THEREFORE, gases having less mass will effuse to a greater extent. Thus, the rate of effusion of the gases will be in the order `:`
`H_(2) gt CH_(4) gt SO_(2)`
`:.` the order of partial pressures in the container will be `: p SO_(2) gt pCH_(4) gt pH_(2)`


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