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0.5 g of fuming H2SO4 (oleum) is diluted with water. This solution is completely neutralized by 26.7 mL of 0.4 N KOH. The percentage of free SO3 in the sample is |
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Answer» 0.5 g of fuming H2SO4 (oleum) is diluted with water. This solution is completely neutralized by 26.7 mL of 0.4 N KOH. The percentage of free SO3 in the sample is |
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