1.

0.440 g of a substance dissolved in 22.2 g of benzene lowered the freezing point of benzene by 0.567^(@)C. The molecular mass of the substance (K_(f)=5.12^(@)kg C mol^(-1))

Answer»

`178.9`
`177.8`
`176.7`
`175.6`

SOLUTION :`m=(K_(F)XX w xx1000)/(Delta T_(f)xx W)=(5.12xx0.440xx1000)/(0.567xx22.2)=178.9`


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