1.

0.44 g of a monohydric alcohol when added to methylmagnesium iodide in ether liberates at S.T.P.,112 cm^(3) of methane. With PCC the same alcohol forms a carbonyl compound that answers silver mirror test. The monohydric alcohol is

Answer»

`H_3C - UNDERSET(OH)underset(|)CH-CH_2 - CH_3`
`(CH_3)_3C - CH_2OH`
`H_3C - underset(OH)underset(|)CH-CH_2-CH_2-CH_3`
`(CH_3)_2CH - CH_2OH`

SOLUTION :


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