1.

`0.44 g` of a hydrocarbon on complete combustion with oxygen gave `1.8 g` of water and `0.88 g` of carbon dioxide. Show that these result are in agreement with the law of conservation of mass.

Answer» Mass of carbon in `0.88 g` of `CO_(2)=(12)/(44) xx 0.88 g = 0.24 g`
Mass of hydrogen in `1.8 g` of `H_(2)O=(2)/(18)xx1.8 g = 0.20 g`
Mass of carbon and hydrogen present in the products `= 0.24+0.20 = 0.44 g`
Mass of hydrocarbon `(C_(x)H_(y))` reacted `= 0.44 g`
Since there is no change in the total mass of carbon and hydrogen as a result of the reaction, this proves the law of conservation of mass.


Discussion

No Comment Found

Related InterviewSolutions