1.

0.36g of an organic compound containing sulphur produced H_(2)SO_(4) by Carius method, which on treatment with BaCl_(2) produced quantitatively 0.2330g of BaSO_(4). Calculate the percentage of S in the compound. (Ba= 137, S= 32, O= 16)

Answer»

SOLUTION :Moles of S in `BaSO_(4) = 1 XX` moles of `BaSO_(4)`
`=(0.2330)/(233)= 0.001 (BaSO_(4)= 233)`
WEIGHT of `S= 0.001 xx 32G`
`=0.032g`
% of `S= (0.032)/(0.36) xx 100= 8.89%`


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