1.

0.32 g of a metal on treatment with an acid gave 112 mL of hydrogen at NTP. Calculate the equivalent weight of the metal

Answer»

58
32
11.2
24

Solution :Equivalent WEIGHT of a metal is the mass of the metal which produces 11200 mL of `H_(2)` at NTP.
112 ml of `H_(2)` at NTP are PRODUCED from metal
`=0.32 g`
`therefore 11200` mL of `H_(2)` will be produced from metal
`=(0.32)/(112)xx11200`
= 32 g


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