0.3 kg of hot coffee , which is at 70^@Cis poured into a cap of mass 0.12 kg. Find the final equilibrium temperature . Take room temperature as 20^(@)C , S_("coffee") = 4080J//kg - K and S_("cup")=1020J//kg - K

0.3 kg of hot coffee , which is at 70^@Cis poured into a cap of mass 0

1.	0.3 kg of hot coffee , which is at 70^@Cis poured into a cap of mass 0.12 kg. Find the final equilibrium temperature . Take room temperature as 20^(@)C , S_("coffee") = 4080J//kg - K and S_("cup")=1020J//kg - K
Answer» `45^@C` `55^@C` `65^@C` none of these Answer :C