1.

0.2 m aqueous solution of a weak acid (HX) is 20% dissociated. The boiling point of this solution is ( K_(b) for water = 0.52 Km^(-1))

Answer»

`101.04^(@)C`
`100.104^(@)C`
`100.1248^(@)C`
`100.52^(@)C`

Solution :`{:("HX(AQ)",rarr,"H"^(+),+,"X"^(-)),(m(1-0.20),,m(0.20),,m(0.20)):}`
MOLAL CONC. of soln.
`=m(1-0.20)+0.20m +0.20m`
`=1.20m`
`DeltaT_(b)=K_(b) xx m`
`=0.52 xx 1.20(0.2)=0.1248`
Boiling point `=100.1248^(@)C`


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