1.

0.1M copper sulphate solution in which copper electrode is dipped at 25^(@)C. Calculate the electrode potential of copper. [Given: E_(Cu^(2+)"|"Cu)^(@)=0.34]

Answer»

SOLUTION :Give that
` [Cu^(2+)] = 0.1M `
` E_(Cu^(2+|Cu^(@) = 034 `
` E_("cell") = ? `
Cell reaction is
` Cu_(aq)^(2+) + 2e^(-) to Cu_((s))`
` E_("cell")= E^(@) - ( 0.0591)/N log ([Cu])/([Cu^(2+)])`
` = 0.34 (0.0591)/2 log 1/(0.1)`
= 0.34 - 0.0294
0.31 V


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