1.

0.1914g of an organic acid is dissolved in approx. 20 ml of water. 25 ml of 0.12 N NaOH required for the complete neutralization of the acid solution. The equivalent weight of the acid is

Answer»

65
64
63.8
62.5

Solution :VOLUME`=25ml=(25)/(1000)`LITRE
NORMALITY`=(wt)/(eq.wtxxvolume)implies0.12=(0.1914xx1000)/(Exx25)`
eq.wt.`=(0.1914xx1000)/(0.12xx25)=63.8`.


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