1.

0.1 mole of CH3NH2(Kb=5×10−4) is mixed with 0.08 mole of HCl and diluted to one litre. What will be the H+ concentration in the solution? log 5 =0.6989log 2= 0.301010−10.09=8.128×10−11

Answer»

0.1 mole of CH3NH2(Kb=5×104) is mixed with 0.08 mole of HCl and diluted to one litre. What will be the H+ concentration in the solution?

log 5 =0.6989

log 2= 0.3010

1010.09=8.128×1011



Discussion

No Comment Found