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0.1 M HCl and 0.1 M `H_(2)SO_(4)`, each of volume 2 ml are mixed and the volume is made up to 6 ml by adding 2 ml of 0.01 N NaCl solution. The pH of the resulting mixture isA. `1.17`B. `1.0`C. `0.3`D. log 2 - log 3 |
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Answer» Correct Answer - B 2 ml of 0.1 M HCl = 0.2 millimole of HCl = 0.2 millimole of `H^(+)` ion 2 ml of 0.1 M `H_(2)SO_(4)= 0 .2` millimole of `H_(2)SO_(4)` = 0.4 millimole of `H^(+)` ion Total `H^(+)` ions = 0.6 millimole Total volume = 6 ml `:. [H^(+)]=(0.6)/(6)M=0.1 M = 10^(-1)M :. pH = 1`. |
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