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0.049 g of `H_(2)SO_(4)` is dissolved per litre of the given solution . Calculate the pH of the solution. |
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Answer» Correct Answer - `3.0` `[H_(2)SO_(4)]=(0.049)/(98) "mol" L^(-1)=5xx10^(-4)M`. As `H_(2)SO_(4)rarr2H^(+)+SO_(4)^(2-), [H^(+)]=2xx(5xx10^(-4))=10^(-3)M :. pH = 3` |
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